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circle simplify the expression: { 3 n + 2 [ n + 6 ( 1 - n ) ] } - 1 =___rea
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Kranx


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Registered: 06.09.2006
From:

Posted: Monday 20th of Aug 20:58    

Hello people . How do you guys do circle simplify the expression: { 3 n + 2 [ n + 6 ( 1 - n ) ] } - 1 =___rea so easily? I just never seem to be able to solve a problem without going wrong a couple of times times. Please do not tell me to take extra classes . They are expensive and I cannot afford them. Any other idea would be more than welcome.
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ameich


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Registered: 21.03.2005
From: Prague, Czech Republic

Posted: Tuesday 21st of Aug 17:28    

If you can be explicit about circle simplify the expression: { 3 n + 2 [ n + 6 ( 1 - n ) ] } - 1 =___rea, I could provide help to solve the math problem. If you don’t want to pay for a algebra tutor, the next best option would be a correct computer program which can help you to solve the problems. Algebrator is the best I have come upon which will elucidate every step of the solution to any math problem that you may enter from your book. You can simply represent as your homework assignment. This Algebrator should be used to learn math rather than for copying answers for assignments.
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Dolknankey


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Registered: 24.10.2003
From: Where the trout streams flow and the air is nice

Posted: Wednesday 22nd of Aug 07:15    

I am a student turned professor ; I give classes to junior school children. Along with the traditional mode of explanation, I use Algebrator to solve examples practically in front of the learners .
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NucitParotj


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Registered: 24.10.2002
From:

Posted: Thursday 23rd of Aug 18:22    

I am not trying to run away from my difficulties. I do admit that dozing off is not a solution to it either. Please let me know where I can find this piece of software.
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Paubaume


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Registered: 18.04.2004
From: In the stars... where you left me, and where I will wait for you... always...

Posted: Friday 24th of Aug 10:14    

It is really good if you think so. You can find the software here https://mathpoint.net/intermediate-algebra-syllabus.html.
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